One object is at rest, and another is moving. The two collide in a one-dimensional, completely inelastic collision. In other words, they stick together after the collision and move off with a common velocity. Momentum is conserved. The speed of the object that is moving initially is 30 m/s. The masses of the two objects are 3.0 and 7.6 kg. Determine the final speed of the two-object system after the collision for the case (a) when the large-mass object is the one moving initially and the case (b) when the small-mass object is the one moving initially.
Case A
when large-mass object is moving
m1 = 7.6 kg
m2 = 3.0 kg
v1 = initial velocity of m1 = 30 m/sec
v2 = 0, in case 1
So using momentum conservation:
Pi = Pf
m1v1 + m2v2 = (m1 + m2)*V
V = (m1v1 + m2v2)/(m1 + m2)
Using given values:
V = (7.6*30 + 3.0*0)/(7.6 + 3.0)
V = 21.51 m/sec = Final Speed of the two-object system
Part B
when small-mass object is moving
m1 = 7.6 kg
m2 = 3.0 kg
v1 = initial velocity of m1 = 0 m/sec
v2 = 30 m/sec, in case 2
So using momentum conservation:
Pi = Pf
m1v1 + m2v2 = (m1 + m2)*V
V = (m1v1 + m2v2)/(m1 + m2)
Using given values:
V = (7.6*0 + 3.0*30)/(7.6 + 3.0)
V = 8.49 m/sec = Final Speed of the two-object system
Please Upvote.
Get Answers For Free
Most questions answered within 1 hours.