Question

Lab Purpose: Determine the specific heat of an unknown metal by using the principle of thermal...

Lab Purpose: Determine the specific heat of an unknown metal by using the principle of thermal equilibrium.

Question: Calculate the percent error between the experimental and theoretical values

Aluminum Calorimeter

Mass

Tf

Ti

Specific Heat

52.5

25.3

22.4

900

Water

Mass

Tf

Ti

Specific Heat

146.5

25.3

22.4

4186

Metal

Mass

Tf

Ti

Specific Heat

65

25.3

100

394.5

Homework Answers

Answer #1

Summary:-

The percentage error of any value can be calculated using a general formula of % error.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Specific Heat Experiment: Calculate the percent error between the experimental and theoretical values Based on the...
Specific Heat Experiment: Calculate the percent error between the experimental and theoretical values Based on the expected values, what is the most likely metal? Procedure Metal A: Aluminum Calorimeter Mass Tf Ti Specific Heat 52.5 25.4 22.6 900 Water Mass Tf Ti Specific Heat 147.5 25.4 22.6 4186 Metal Mass Tf Ti Specific Heat 64.5         25.4 100 38.7 Procedure Metal B: Aluminum Calorimeter Mass Tf Ti Specific Heat 52.5 25.3 22.4 900 Water Mass Tf Ti Specific Heat 146.5 25.3...
A lab student has an unknown metal with a mass of 227 g that they want...
A lab student has an unknown metal with a mass of 227 g that they want to identify. The student places the metal in boiling water (100? ?) and lets it come to equilibrium (i.e. the metal is the same temperature as the water). The student then places the metal in a beaker of water with a mass of 300g and an initial temperature of 20? ?. The beaker of water comes to a final temperature of 40 0C. Determine...
A student doing an experiment pours 0.500 kg of heated metal whose temperature is 98.0 oC...
A student doing an experiment pours 0.500 kg of heated metal whose temperature is 98.0 oC into a 0.356 kg aluminum calorimeter cup containing 0.418 kg of water at 28.0 °C. The mixture (and the cup) comes to thermal equilibrium at 38.0 °C. The specific heat of the metal is ________ J/kg oC. (specific heat of aluminum = 900 J/kg oC, specific heat of water = 4186 J/kg oC)
An unknown metal of mass 0.280 kg is heated to 160.0°C and dropped in an aluminum...
An unknown metal of mass 0.280 kg is heated to 160.0°C and dropped in an aluminum calorimeter of mass 0.250 kg that contains 0.170 kg of water at 30°C. The calorimeter, water, and unknown metal have a final temperature of 46.0°C. Find the specific heat of the unknown metal. Hint: you need the specific heat of water and aluminum. Use units of [J/(kg.K)] and the values in your book for the specific heat.
In a calorimetry experiment to determine the specific heat capacity of a metal block, the following...
In a calorimetry experiment to determine the specific heat capacity of a metal block, the following data was recorded: Quantity Mass of the metal block 0.50 kg Mass of empty calorimeter + Stirrer 0.06 kg Mass of calorimeter + stirrer + water 0.20 kg Mass of water 0.14 kg Initial Temperature of metal block 55.5 ⁰C Initial Temperature of water and calorimeter 22 ⁰C Final Temperature of block- water system 27.4 ⁰C Take the specific heat capacity of water to...
Data Sheet Table 1. Steel Bolt Specific Heat Data Bolt Ti (°C) Water Ti (°C) Water...
Data Sheet Table 1. Steel Bolt Specific Heat Data Bolt Ti (°C) Water Ti (°C) Water and Bolt Tf (°C) Water ΔT = Tf - Ti Bolt ΔT (°C) Bolt Mass (kg) Water Mass (kg) Steel Bolt 72 20 23 3 72 .021 .15 Post-Lab Questions A. The heat lost by the hot bolt is equal to the heat gained by the water in the calorimeter. Use the equations provided above and what you know about heat to solve for...
SETUP In today’s lab we will measure specific heat using a calorimeter. A calorimeter consist of...
SETUP In today’s lab we will measure specific heat using a calorimeter. A calorimeter consist of a small metal cup inside a larger metal container, with a lid.  The cups are thermally separated from each other by means of air and a wooden ring, thus reducing the thermal conduction to a minimum. To keep track of how much water etc. we have, the whole calorimeter will be placed on a digital scale. Make sure to zero the scale before you place...
An unknown substance has a mass of 0.125 kg and an initial temperature of 79.8°C. The...
An unknown substance has a mass of 0.125 kg and an initial temperature of 79.8°C. The substance is then dropped into a calorimeter made of aluminum containing 0.285 kg of water initially at 21.0°C. The mass of the aluminum container is 0.150 kg, and the temperature of the calorimeter increases to a final equilibrium temperature of 32.0°C. Assuming no thermal energy is transferred to the environment, calculate the specific heat of the unknown substance.
An unknown substance has a mass of 0.125 kg and an initial temperature of 92.5°C. The...
An unknown substance has a mass of 0.125 kg and an initial temperature of 92.5°C. The substance is then dropped into a calorimeter made of aluminum containing 0.285 kg of water initially at 27.0°C. The mass of the aluminum container is 0.150 kg, and the temperature of the calorimeter increases to a final equilibrium temperature of 32.0°C. Assuming no thermal energy is transferred to the environment, calculate the specific heat of the unknown substance.
Lab 2: Specific Heat of Metals A 220 oC metal object is added to 82.5 mL...
Lab 2: Specific Heat of Metals A 220 oC metal object is added to 82.5 mL of water. The water rises in temperature from 23.9 oC to a maximum temperature of 27.1 oC. What is the specific heat of the metal if it weighs 55.2 g? Assume the heat absorbed by the calorimeter is negligible. (density of water = 1.00 g/mL) Group of answer choices 0.779 JgoCJgoC -0.104 JgoCJgoC 0.0910 JgoCJgoC 0.104