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the weight of 90 m3 of water in the Pacific at a great depth is 900000...

the weight of 90 m3 of water in the Pacific at a great depth is 900000 N, what is the pressure at this depth if the specific gravity on the surface is 0.99

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Answer #1

WE KNOW PRESSURE= FORCE /AREA

                DENSITY OF SURFACE * g * HEIGHT = FORCE/AREA

                ie height = FORCE/(AREA * HEIGHT*g* density of surface)

                            = 9*10^5/(90*10*1000*.99)

                        h= 1.01m

ie pressure   = .99*1000*10*1.01

                   =9999N/m^2

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