Question

The frequency of a light wave in air is 5.7 × 1014 ????. What is the wavelength of this wave after it enters a pool of water (refractive index n = 1.33)?

Answer 1

Since,

frequency(f) = c/

here, f = frequency in air = 5.7*10^14 Hz

c = speed of light in air = 3*10^8 m/s

= wavelength in air = ??

So,

= c/f = (3*10^8)/(5.7*10^14)

= 5.263*10^-7 m

now, in water,

' = /n

given, n = refractive index = 1.33

then,

' = wavelength in water = (5.263*10^-7)/1.33

' = 3.957*10^-7 m = 395.7*10^-9 m = 395.7 nm

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