Question

An electron moves with a velocity, v = ( 4i + 2 j)x106 m/s in a...

An electron moves with a velocity, v = ( 4i + 2 j)x106 m/s in a region where there is a uniform magnetic field, B = (0.5 j) T. (a) Find the magnitude and direction of the force acting on the electron as it enters into the magnetic field.(b) Find the pitch of the helical motion. (c) What is the work done by the magnetic force during 1 cycle of the motion? (e = - 1.6x10-19 C, me = 9.10 x10-31 kg).

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
An electron has velocity V = (29i + 38j) km/s as it enters a uniform magnetic...
An electron has velocity V = (29i + 38j) km/s as it enters a uniform magnetic field B= 50 i µT. What are (a) the radius of the helical path taken by the electron and (b) the pitch of that path? (c) To an observer looking into the magnetic field region from the entrance point of the electron, does the electron spiral clockwise or counterclockwise as it moves? The charge of an electron is -1.602 × 10-19 C and its...
An electron with a velocity given by v⃗ =(1.6×105 m/s )x^+(6700 m/s )y^ moves through a...
An electron with a velocity given by v⃗ =(1.6×105 m/s )x^+(6700 m/s )y^ moves through a region of space with a magnetic field B⃗ ==(0.26 T )x^−(0.10 T )z^ and an electric field E⃗ =(220 N/C )x^. Using cross products, find the magnitude of the net force acting on the electron. (Cross products are discussed in Appendix A.) Express your answer using two significant figures.
An electron is accelerated in the positive x direction through a potential difference of 160 V....
An electron is accelerated in the positive x direction through a potential difference of 160 V. It then enters a region with a uniform magnetic field of 0.80 T in the positive z direction. (a) What is the speed of the electron? (b) What is the magnitude and direction of the magnetic force on the electron?
An electron moves at 2.70×106 m/s through a region in which there is a magnetic field...
An electron moves at 2.70×106 m/s through a region in which there is a magnetic field of unspecified direction and magnitude 7.10×10−2 T What is the largest possible magnitude of the acceleration of the electron due to the magnetic field IN M/S^2?)
An electron moves through a uniform magnetic field given by = Bx i ̂ +(4.52 Bx)...
An electron moves through a uniform magnetic field given by = Bx i ̂ +(4.52 Bx) j ̂ . At a particular instant, the electron has velocity v → = (2.66 i ̂ +4.30 j ̂ ) m/s and the magnetic force acting on it is (4.31 × 10-19) k ̂ N. Find Bx.
An electron (q=-1,6x10-19C, m=9,1x10-31kg) enters a uniform magnetic field, whih is in +x axis and it...
An electron (q=-1,6x10-19C, m=9,1x10-31kg) enters a uniform magnetic field, whih is in +x axis and it has magnitude of 2T. At t=0, the velocity components vx=3x105m/s, vy=4x105m/s and vz=0. a-At t=0 calculate the magnetic force acting on proton and its acceleration. b- Calculate the Radius of helical path c- Calculate the angular velocity d- Calculate the pitch of helix. (0=4x10-7 MKS) Help quickly I get you thumbs up directly
10- A particle moving at speed of 3x105 m/s enters perpendicularly in to a uniform magnetic...
10- A particle moving at speed of 3x105 m/s enters perpendicularly in to a uniform magnetic field of 0.10 tesla .what is the magnitude and the direction of magnetic force acting on the particle by the magnetic field . a) The particle is an electron. b) The particle is a proton.
An electron moves at 2.50 x 106 m/s through a region in which there is a...
An electron moves at 2.50 x 106 m/s through a region in which there is a magnetic field of unspecified direction and magnitude 7.40 x 10-2 T. (a) What is the smallest possible magnitude of the acceleration of the electron due to the magnetic field?(1.5 marks) (b) What is the largest possible magnitude of the acceleration of the electron due to the magnetic field? (c) If the actual acceleration of the electron is one-fourth of the largest magnitude in part...
An electron is accelerated through 2,200 V from rest and then enters a region where there...
An electron is accelerated through 2,200 V from rest and then enters a region where there is a uniform 1.50 T magnetic field. What are the maximum and minimum magnitudes of the magnetic force acting on this electron? A) maximum in N B) minimum in N
An electron is accelerated through 2200 V from rest and then enters a region where there...
An electron is accelerated through 2200 V from rest and then enters a region where there is a uniform 1.80 T magnetic field. What are the maximum and minimum magnitudes of the magnetic force acting on this electron? (a) maximum _______ N (b) minimum _______ N
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT