Question

In the Newtons 2nd law lab the acceleration of the cart was plotted as a function...

In the Newtons 2nd law lab the acceleration of the cart was plotted as a function of the hanging mass, and the slope of the graph was calculated. What were the units of the slope?

Group of answer choices

cms2

kgs2cm

kgcms2

Homework Answers

Answer #1

please Up Vote. otherwise , just comment down the problem/confusion . I will get back to you asap.

Please note that in my solution I have shown explicitly that what will be the unit of slope in both cases for your reference

1. if acceleration - y axis  

mass - x axis

2. mass - y axis

acceleration - x axis .

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
I did a lab on Newton’s second law. The procedure went something like this Procedure: 1.)...
I did a lab on Newton’s second law. The procedure went something like this Procedure: 1.) Tare the force sensor attached to the cart. 2.) Attach 100 g to the string and attach the other end to the force sensor atop the cart. 3.) Allowing the weight to hang freely, from the end of the string that is attached to the force sensor, start recording data while holding the cart in place to capture T0 4.)Release the cart, this allows...
1. In Newton’s 2nd law experiment, a student measured the acceleration of the glider and the...
1. In Newton’s 2nd law experiment, a student measured the acceleration of the glider and the weight of the hanging mass. In this experiment, the air track was on and there was no drag force acting on the glider. The student results are shown below: F (N) a (m/s2) 0.100 0.100 0.200 0.250 0.300 0.450 0.400 0.600 0.500 0.800 a. Use Excel to plot the data and use the linear fit to find the slope. b. Use your findings to...
A cart of mass m1(pictured) is free to move nearly frictionless up a ramp at angle...
A cart of mass m1(pictured) is free to move nearly frictionless up a ramp at angle θ. A small mass m2 hangs from a string that runs over a pulley and connects to m1. We will determine the acceleration of the cart m1 over a known distance x,then plot the acceleration of m1 as a function of the hanging mass m2. a) The hanging mass will create a constant pulling force to accelerate the cart up the ramp. Using Newton’s...
Exploration 2.1 Suppose the cart and masses can be changed by adding masses to the cart....
Exploration 2.1 Suppose the cart and masses can be changed by adding masses to the cart. Sketch a graph of the acceleration plotted vs. cart masses in the space below based on your equation in part 1.1e. Equation is   mhg=(mc+mh)a. a=mhg/mc+mh Exploration 2.2 If you were to take data, measuring the acceleration of the cart for different masses added to the cart, what could you plot that would give you a straight line? What would be on the x-axis? What...
A cart with a total mass of 300g is on low-friction track with a string attached...
A cart with a total mass of 300g is on low-friction track with a string attached to mass of 100g hanging over a low friction pulley? The cart and hanging weight are held in place and then released. 1. what is the acceleration of the cart after it is released Express your answer in SI units keeping the correct number of significant figures.
A group of students performed the same "Newton's Second Law". They obtained the following results: m1(kg)...
A group of students performed the same "Newton's Second Law". They obtained the following results: m1(kg) t1(s) v1(m/s) t2(s) v2(m/s) 0.050 1.2000 0.2500 1.7733 0.4378 0.100 1.2300 0.3240 1.6288 0.6690 0.150 1.1500 0.3820 1.4751 0.8485 0.200 1.1100 0.4240 1.3937 0.9558 where m1 is the value of the hanging mass (including the mass of the hanger), v1 is the average velocity and t1 is the time at which v1 is the instantaneous velocity for the first photogate, and v2 is the...
The current i(t) in amps as a function of time t in seconds is plotted above...
The current i(t) in amps as a function of time t in seconds is plotted above for an ideal L-C circuit (zero resistance). At t = 6 s as indicated by the dashed vertical line, the current is i = –0.84 A. The current amplitude is 3 A. Approximately what percentage of the total energy in this circuit is stored in the magnetic field of the inductor at this point? Group of answer choices 8% 17% 84% 28%
Hooke’s Law Hooke's Law For this lab you need to plot a graph of Force( y...
Hooke’s Law Hooke's Law For this lab you need to plot a graph of Force( y axis) versus elongation (x axis) for a spring. The graph of force vs elongation for spring should be a straight line (Hooke's law). From the slope determine the elastic constant, k. If you are not using Excel, draw your graphs by hand, scan or take a picture and insert the graph in the lab report. Your graph should have a title, and the axis...
This question is from a physics lab on Gravitational Acceleration. Given that each tick from a...
This question is from a physics lab on Gravitational Acceleration. Given that each tick from a spark timer occurs at one sixtieth of a second, get the slope in units of cm/sec^2. Compare your answer with the standard value of 980 cm/sec^2by computing the percentage difference. Our lab data for instantaneous velocity gives us a best fit line with and equation of y=.5223 + 2.0692 giving a slope of .5223 cm/ticks^2. This conversion seems as if it should be pretty...
4. Use the formula for the acceleration found at point 3 to calculate the “calculated acceleration”...
4. Use the formula for the acceleration found at point 3 to calculate the “calculated acceleration” in Data Table for any given hanging mass m. 5. Determine the percentage difference between the values of acceleration calculated using the equation at point 3) and the values measured using the experiment. %error = | ameasured − acalculated| ×100 / acalculated and write them in the table. PART III: CONCLUSIONS 1. Give a reasonable explanation for your percent difference. What can be the...