Question

Find the total capacitance of the combination of capacitors shown in the figure below.

(C₁ = 2.92

Answer 1

Capacitance in parallel = Ct = C1 +C2 + C3

Capacitance in series = 1 / Ct = 1/C1 + 1/ C2 +1/ C3 +.........

On the left side , 5.0 mu F in series with 3.5 mu F

1/ Ct = 1/5 + 1 /3.5

1/Ct = 0.4857

Ct = 2.059 mu F

Right side we have 15 mu F in parallel wuth 0.75 mu F

Ct = 15 + 0.75 = 15.75 mu F

15.75 on series with 1.5 = 1.370 mu F

We also have that big 8.0 mu F in the middle which is in parallel with both of the above. we have

2.059 mu F in parallel with 8.0 mu F in parallel with 1.370 mu F

2.059+ 8. 0+ 1.370 = 11.429 mu F

total C = 11.429 mu F