Question

Ray Tracing - Lens On the diagram below or on a separate sheet of paper, generate...

Ray Tracing - Lens

  • On the diagram below or on a separate sheet of paper, generate a ray diagram for an object 5 cm high and a distance 20 cm left of diverging lens 1 with focal length (-)10 cm. Converging lens 2 is separated from lens 1 by 13.33 cm and has focal length +10 cm.
  • Use the thin lens formula to calculate the final image position and image height. (use sheet back if necessary)
  • Is the image real or virtual?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
On a graph paper, draw a ray diagram of the following setup, making sure you have...
On a graph paper, draw a ray diagram of the following setup, making sure you have proper scaling. In addition, find the location with respect to the first objective and height of the final image. An 5.0 cm tall object is 10 cm in front of a converging lens with a focal length of 5.0 cm. 20 cm behind the converging lens is a diverging lens with a focal length of 10 cm. 20 cm behind the diverging lens is...
A converging lens, which has a focal length equal to 8.4 cm, is separated by 30.5...
A converging lens, which has a focal length equal to 8.4 cm, is separated by 30.5 cm from a second lens. The second lens is a diverging lens that has a focal length equal to -13.7 cm. An object is 16.8 cm to the left of the first lens. (a) Find the position of the final image using both a ray diagram and the thin-lens equation. __________cm to the right of the object (b) Is the final image real or...
A converging lens with focal length of 30 cm and a diverging lens with focal length...
A converging lens with focal length of 30 cm and a diverging lens with focal length of 10 cm are 15 cm apart. A 4-cm-tall object is 10 cm in front of the 30-cm-focal-length lens. Use ray tracing to find the height of the image in cm
An optical system consists of two lenses separated by 35 cm – first is converging with...
An optical system consists of two lenses separated by 35 cm – first is converging with focal length 10 cm and the second is diverging with focal length 15 cm. An object is 20 cm to the left of the first lens. Find the position of the final image using both a ray diagram and the thin-lens equation. Is the image real or virtual? Erect or inverted? What is the overall magnification of the image?
A converging lens and a diverging lens, separated by a distance of 30.0 cm, are used...
A converging lens and a diverging lens, separated by a distance of 30.0 cm, are used in combination. The converging lens has a focal length of 15.2 cm. The diverging lens is of unknown focal length. An object is placed 19.3 cm in front of the converging lens; the final image is virtual and is formed 12.0 cm in front of the diverging lens. What is the focal length of the diverging lens?
A 1.0 cm tall object is 2.0 cm in front of a converging lens with a...
A 1.0 cm tall object is 2.0 cm in front of a converging lens with a focal length of 3.0 cm. A. Determine the image position and height by using ray tracing to find image B. Calculate the image position and height
Principal Ray Diagrams and Equations 1.) An object is 6 cm in front of a convex...
Principal Ray Diagrams and Equations 1.) An object is 6 cm in front of a convex mirror with a focal length of 10 cm. a.) Use ray tracing alone to determine the location and magnification of the image. Is the image upright or inverted? Is it real or virtual? b.) Use equations alone to determine the location and magnification of the image. Is the image upright or inverted? Is it real or virtual? 2.) A 2.0-cm-tall object is 20 cm...
Make a ray diagram to show the following: a converging lens of 15 cm fixed focal...
Make a ray diagram to show the following: a converging lens of 15 cm fixed focal length is placed on an optical bench of 200cm in length. An object is placed at 0.0cm and a screen is placed at 140 cm.... a) measuring from the object end of the bench determine two positions to locate the lens so that the image on the screen will be in focus. draw and label on diagram. b) on a separate ray diagram (same...
A diverging lens with a focal length of -19.7 cm and a converging lens with a...
A diverging lens with a focal length of -19.7 cm and a converging lens with a focal length of 11.0 cm have a common central axis. Their separation is 39.5 cm. An object of height 1.1 cm is 26.4 cm in front of the diverging lens, on the common central axis. Find the location of the final image produced by the combination of the two lenses. Where is the image located as measured from the converging lens? What is the...
A converging lens of focal length f1 = +22.5 cm is placed at a distance d...
A converging lens of focal length f1 = +22.5 cm is placed at a distance d = 60.0 cm to the left of a diverging lens of focal length f2 = −30.0 cm. An object is placed on the common optical axis of the two lenses with its base 45.0 cm to the left of the converging lens. (The thin-lens approximation may be assumed to hold.) (a) Calculate the location of the final image and its overall magnification with respect...