Question

3.1×10²³ electrons move through a calculator in 5.0 hours.

A) Determine the magnitude of the total charge that flows through the calculator during the specified time.

B) Determine the magnitude of the flow rate of charge.

Answer 1

Solution :

Given :

Number of electrons (n) = 3.1 x 10²³ electrons

Time taken (t) = 5 hours = 5 x 3600 sec = 18000 sec = 1.8 x 10⁴ sec

Part (a) Solution :

Since the charge on each electron is (e) = 1.6 x 10^-19 C

Therefore : the total charge that flows through the calculator during the specified time (Q) = n e

Thus : Q = (3.1 x 10²³)(1.6 x 10^-19 C) = 4.96 x 10⁴ C

Part (b) Solution :

the magnitude of the flow rate of charge = Q / t = (4.96 x 10⁴ C) / (1.8 x 10⁴ sec) = 2.76 Amps