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A bar of some material has a cross sectional area of A and an original length...

A bar of some material has a cross sectional area of A and an original length of L. A tensile force of F is applied to the bar, producing a deformation of ΔL. A bar with the same original length but with twice the cross sectional area has the same force of F applied to it. The deformation of the second bar is

Group of answer choices

0.5 (ΔL)

0.25 (ΔL)

ΔL

2 (ΔL)

4 (ΔL)

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Answer #1

As young modulus will remain same for a material,using this change in length is calculated.

Young modulus is given by stress/strain.

Where, stress =force /area

& strain =change in length /original length.

Change in length is comes out to be 0.5(∆L)

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