What is the angular momentum of a 2.8-kg uniform cylindrical grinding wheel of radius 29 cm when rotating at 1200 rpm ?
How much torque is required to stop it in 4.0 s ?
Given the mass of the wheel m = 2.8kg, the radius of the wheel r = 29cm and the wheel is rotating at 1200rpm. The frequency of ration is,
The angular speed of the wheel is,
The angular momentum of the wheel is given by,
So the angular momentum of the wheel is 29.59kgm^2/s.
The torque required to stop the wheel in t = 4s is,
Since the wheel comes to rest, the final angular momentum is zero.
So the magnitude of torque required to stop the wheel is 7.4Nm.
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