Question

An electron flies out of a point of an electric field, where the electric potential is 0 = 600V, with the velocity v = 1,2x10^7 m/s in the direction of the field lines. Find the electric potential in a point where the speed of the electron is zero.

Answer #1

An electron is traveling through a uniform electric
field. The constant electric field is given by . At t = 0, the
electron is at (0, 0) and traveling in the positive z direction
with a speed of 5 m/s. a) What is its position 5.0 s later? b) What
is the magnitude and direction of the particle's velocity at 5.0
s?
EDIT:
Oops!
E = (-3.00 x 10^-11 N/C)i - (2.00 x 10^-11 N/C) j + (1.00 x
10^-11...

An electron is initially at ground level, and the electric
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(9.8 N/kg pointing down). Only gravity and the electric force are
relevant.
a) If the electron is given an initial upward speed of 30 m/s,
what is the maximum height above the ground that it...

An electron, a neutron(which has zero charge) and a proton are
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negligible.
We know that: (Choose the correct answers)
the acceleration of the electron is in the +x direction.
the x coordinate of the electron is less...

You cause a particle to move from point A, where the electric
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An electron is traveling through a uniform electric field. The
field is constant and given by E⃗
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the origin and traveling in the x direction with a speed of 2.20
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The electric potential in a region of space as a function of
position x is given by the equation V(x) =
αx2 + βx - γ, where α =
2V/m2, β = 7V/m, and γ =
15V. All nonelectrical forces are negligible.
An electron starts at rest at x = 0 and travels to
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Calculate the magnitude of the work done on the electron by the
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Which of the followings all point in the same direction?
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The potential at point P in an electric field is 300 V. (Let's
denote the electric potential energy as UE.)
(a) What is the electrical potential energy of a proton placed
at P, in eV and in joules?
Ue=
Ue=
(b) What is the electrical potential energy of an electron at P,
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Ue=
Ue=

In a certain region of space the electric potential is
given by V=+Ax2y−Bxy2, where A =
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Calculate the magnitude of the electric field at the
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Calculate the direction angle of the electric field at
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An electron has an initial speed of
8.03 106 m/s in a uniform
4.38 105 N/C strength electric field. The
field accelerates the electron in the direction opposite to its
initial velocity.
(a) What is the direction of the electric field?
_opposite direction to the electron's initial velocity
_same direction as the electron's initial
velocity
_not enough information to decide
(b) How far does the electron travel before coming to rest?
_m
(c) How long does it take the electron to come...

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