A wire 2.80 m in length carries a current of 4.20 A in a region where a uniform magnetic field has a magnitude of 0.240 T. Calculate the magnitude of the magnetic force on the wire assuming the following angles between the magnetic field and the current.
(a)60.0 degrees
(b)90.0 degrees
(c)120 degrees
Sol: Force on current carrying conductor kept in magnetic field is given as-
Here L =2.80 m current I = 4.20 A and B = 0.240 T
(a) angle theta = 60.0 degree
Hence Force F is
(b) angle theta = 90.0 degree
Hence Force F is
(c) angle theta = 120 degree
Hence Force F is
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