approximately
1000 times less.


approximately 100
times less.


approximately 10
times less.


about the
same.

1)
the density of air = 1.225 Kg/m^3
which is approximately 1000 times less than water
2)
guage pressure in this care is the pressure excerted my the water
above that point and neglecting the pressure do to atmospheric
air
so guage pressure = rho * g * h
= 1000*9.81*(5*12*2.54/100)
= 14950.44 Pa
3)
the bouyant force exceted on the irregular body is the weight of
liquid displaced by it
which is equal to the volume of the object * density of the liguid
* acceleration due to gravity
density of liquid = 1000 Kg/m^3
so the buoyant force = weight in air  weight in water = 34  15 =
19 N
so 19 = v*1000*9.81
V = 1.936799*10^(3) m^3
V=1936.799 cm^3
4)
let the mass in air be Mg
so
let the mass in water = 0.67Mg
so buoyant force = (Mg0.67Mg) = 0.33Mg
this is equal to the weight of the liquid displaced
0.33Mg = V*1000*g
so M/V = density = 3030.3030 Kg/m^3
5)
volume of sphere = 4/3 * Pi*r*r*r
given diameter = 7.11 cm = 0.0711 m
radius = 0.03555 m
so volume = 4/3 * Pi * 0.03555^3 = 1.8819 * 10^(4) m^3
given mass = 0.627 kg
so density = mass / volume = 0.627 kg / 1.8819 * 10^(4) m^3 =
3331.655 Kg/m^3
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