A 165-N sign is supported by two ropes. One rope pulls up and to the right 35.5° above the horizontal with a tension T1, and the other rope pulls up and to the left 50.5° above the horizontal with a tension T2, as shown in the figure. Find the tensions T1 and T2.
Weight of the sign, W = 165 N (Vertically downward direction)
T1 = ?
1 = 35.5 deg
T2 = ?
2 = 50.5 deg
Total vertical component of the tensions shall be balanced by the weight of the sign.
So, we have -
T1*sin35.5 + T2*sin50.5 = W = 165 N
=> T1*0.58 + T2*0.77 = 165---------------------------------(i)
Horizzontal components of the two tensions shall balance each other.
So -
T1*cos35.5 = T2*cos50.5
=> T1*0.81 = T2*0.64
=> T2 = 1.26*T1-----------------------------------------------(ii)
put the value of T2 from (i) into (ii) -
0.58*T1 + 0.77*1.26*T1 = 165
=> 1.55*T1 = 165
=> T1 = 165 / 1.55 = 106.4 N
So, T2 = 1.26*106.4 = 134.1 N
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