two point charges each have values of +300 and - 3000C and are seperated by a distance of 4.00cm. what is electric field midway between the two charges?
E.F due to +ve charge will be away from charge, E.F due to -ve charge will be towards the charge.
E1 = Electric field at point P ( mid point ) due to charge q1
E1 = K*q1/ r2
= 9*109 *300/ (2*10-2)2 ( k = 1/4*pie*E0 = 9*109 )
= 6.75*1015 N/C
E2 = electric field at P due to charge q2
E2 = k*q2 / r2
= 9*109*3000 / (2*10-2)2
= 6.75*1016 N/C
from fig, E1 and E2 are in same direction:
net electric field, E = E1 +E2 = 7.425*1016 N/C ( towards -ve charge)
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