1)Mass of Carbon = 12 u
Mass of Iron = 55.845 u
The crystal has 0.8% C by mass and 99.2% Fe by mass.
Let the mass of crystal be 'm'. Thus mass of C in this is 0.008m.
thus 1 atom of C will be contained in 12/0.008 u = 1500u.
this will have 1488u of Fe = 26.64 atoms.
thus there will be 1 C atoms for 26.64 Fe atoms. this corresponds to an atomic percentage of 3.75%.
as one fcc unit cell contains 4 atoms, we need to examine ~7 unit cells before encountering a C atom.
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