Question

An electromagnetic wave in a medium is given by the following
wave function expression:
**E**=5E_{0}(**i**-2j)sin(kx-wt).
The wave is known to have a wavelength of 690 nm and frequency of
3.2*10^{14} Hz. Also E_{0}=10^{4} V/m. For
this wave find the propagation number, angular frequency, direction
of propagation, speed of wave, index of refraction of medium,
direction of **E** oscillation, direction of
corresponding **B** oscillation, amplitude of
**E**, amplitude of **B,** and calculate
the irradiance of this wave.

Answer #1

please once check inserted values by me .thank you

The electric field for a sinusoidal electromagnetic wave is
E = E0
sin(ky+wt) i
with E0 =40 V/m and k = 1.40E+8
m-1.
Select the direction of propagation for this wave.
Find the wave number of the wave.
Find the wavelength of the wave.
Find the period of the wave.
Find the frequency of the wave.
Find the angular frequency of the wave.
Find the speed of the wave.
Find the amplitude of the magnetic field.
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