Question

A wheel 1.32 m in diameter rotates at 1225 rpm.

(a) Find the angular in rad/s.

(b) What is the linear speed and acceleration of the point on the
edge of the wheel?

(c) If the wheel travels 12.5 km calculate the number of
revolutions that the wheel

makes.

Answer #1

Diameter of the wheel = D = 1.32 m

Radius of the wheel = R = 0.66 m

Rotation speed of the wheel = N = 1225 rpm

Angular speed of the wheel =

= 128.28 rad/s

Linear speed at the edge of the wheel = V

V = R

V = (128.28)(0.66)

V = 84.665 m/s

Acceleration at the edge of the wheel = a

a =
^{2}R

a = (128.28)^{2}(0.66)

a = 10860.8 m/s^{2}

Distance traveled by the wheel = S = 12.5 km = 12500 m

Number of revolutions made by the wheel = n

n = 3014.3 revolutions

a) Angular speed = 128.28 rad/s

b) Linear speed at the edge of the wheel = 84.665 m/s

Acceleration at the edge of the wheel = 10860.8
m/s^{2}

c) Number of revolutions made by the wheel if it travels 12.5 km = 3014.3 revolutions

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