Question

at the bottom of a dip in a road, a person feels the seat beneath them pressing upward with a force equal to AW, where W is the persons weight. If radius of curvature of the dip is 58.3 m and the car is traveling at 20.5 m/s . What is A?

Answer 1

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R = 58.3 m

v = 20.5 m/s

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At the bottom of the hill : The force acting on the person will be given as : F_net = F_N - W = F_C

∴ F_N - W = m v² / R

∴ AW - W = m v² / R

∴ W (A - 1) = m v² / R

∴ m g (A - 1) = m v² / R

∴ g (A - 1) = v² / R

∴ (9.81 m/s²)(A - 1) = (20.5 m/s)² / (58.3 m)

∴ (A - 1) = 0.736

∴ A = 1.74

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