To use Newton's 2nd law as well as energy conservation for a vertical mass-spring
A proud deep-sea fisherman hangs a 65.0-kgkg fish from an ideal spring having negligible mass. The fish stretches the spring from its initial equilibrium position until it comes to a new equilibrium position, which is 0.120 mm below the initial equilibrium position.
a)Draw a force diagram of the fish at its new equilibrium position. Then use Newton's 2nd law to solve for the spring constant of the spring
b)The fish is now pulled down 5.00 cmcm from the new equilibrium position and released. Solve for the period of the oscillation of the fish.
c)Use energy conservation to solve for the maximum speed of the fish during its oscillation. (Remember that once we account for the “new” equilibrium position, we no longer have to include gravitational potential energy!)
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