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A) A 1132.0 g mass is on a horizontal surface with μk = 0.36, and is...

A) A 1132.0 g mass is on a horizontal surface with μk = 0.36, and is in contact with a massless spring with a force constant of 571.0 N/m which is compressed. When the spring is released, it does 0.71 J of work on the mass while returning to its equilibrium position. Calculate the distance the spring was compressed.

- I got .05 and that was correct

B)What is the velocity of the mass as it loses contact with the spring?

I NEED HELP WITH B

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Answer #1

Given that, Mass, m=1132g Friction Conskype = 8.36 sporing constant k = 5710/m. sporing wood, ks = 0.7150 work done by the spring. Ws= 1 x K x ² x= 12xWs x = 12 x 0.71 = 0.05 m v 571. B. By the conservation of erogy Wst Whoitonak E

0.71 + 4 x mg x x = y mv IK 12 0.71 +0.36% 14432x9.8X0-05 = Yxl 1324 y? 1:42 + 2x 36X1. 132x9.8X0.05 1:132 V2 = 16 = 1:27 m/s Hence the velocity is 1.27m/s.

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