Question

A ball is thrown directly downward with an initial speed of 7.75 m/s, from a height of 29.4 m. After what time interval does it strike the ground?
______________ s

Answer 1

Given:

u = initial speed = 7.75 m/s (downward)

h = height moved = 29.4 m (downward)

g = acceleration due to gravity = 9.81 m/s/s (downward)

Let time taken be 't'.

Using kinematic equation:

On solving we get one positive value of t,

t = 1.78 s.

Therefore, the time taken to reach ground is 1.78 s. [answer]