Calculate the minimum-wavelength x-ray that can be produced when a target is struck by an electron that has been accelerated through a potential difference of 21.0 kV and 1.09 ✕ 102 kV.
(a) 21.0 kV
λmin = m
(b) 1.09 ✕ 102 kV
λmin = m
(c) What happens to the minimum wavelength
as the potential difference increases?
remains the samedecreases increases
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