Question

A worker pushes horizontally on a 600-N shipping container. The container moves across a warehouse floor at a constant velocity of 0.8m/s. The coefficient of kinetic friction between the crate and floor is 0.3. What is the magnitude of the worker's force in N?

PLEASE SHOW STEP BY STEP I AM SO CONFUSED

Answer 1

As the box is moving with constant velocity.that means the acceleration will be zero.So Net force acting on the box should be zero.

So according to formulae

F_net = F_worker -F_K, So in order to become F_Net =0, we should have force exerted by the worker and force due to friction is equal to zero.

normal force= 600N

co efficient of kinetic friction= .3

Now according to question F_K = 600*.3 =180 N= co efficient of kinetic friction * normal force

So worker's force is= 180N