Question

An audio amplfier drives a series RLC circuit consisting of an 8.0 Ω loudspeaker, a C = 42 × 10−10F capacitor, and a L = 60 × 10−6 H inductor. The amplifier output is voltage is 15.0 V at a frequency of f = 106 Hz. The current flowing in the circuit is given by

(a) 0.044 A

(b) 1.875 A

(c) 0.8 A

(d) 12 A

(e) None of the above.

Answer 1

Given values are....

R = 8 ohm

C= 42*10^-10F

L = 60*10^-6 H

V = 15 V.

First calculate impedance and than current following through the circuit.

Option (a.) Is correct. I = 0.044A.

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