Question

*Useful Formulae*

*potential
energy:*
U_{spr} = ½ k (Dx)^{2}

*Conservation of Momentum*:

**p** = m**v**;
m_{1}v_{1} + m_{2}v_{2} =
constant; p(initial) =
p(final);

*For perfectly elastic collisions
ONLY*:

(v_{1i} – v_{2i}) = - (v_{1f} -
v_{2f})

k_{1} = (m_{1} – m_{2}) / m_{1}
+ m_{2}; k_{2}
= 2m_{2};

v_{1f} = k_{1}v_{1i} +
k_{2}v_{2i};
v_{2f} = k_{2}v_{1i} +
k_{1}v_{2i};

*Rocket Equation*

Thrust =
|dm/dt|*v_{exh};
v_{final} = v_{initial} + v_{exh}*ln
(M_{initial} / M_{final});

[dm/dt] = *kg/sec*;

**3. Perfectly Elastic Collision**. Two masses move
along the x-axis. A sphere of 100 grams moves *to the right*
with a speed of 5.0 m/sec. It collides perfectly with a second
sphere of mass 50 grams, moving *to the left* with a speed
of 10.0 m/sec. Using the provided formulae, calculate the resulting
velocities after the collision.

Answer #1

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