Question

Question 8

This situation is similar to one examined in a lecture. An object of mass 1.22 kg falls without rotating from rest through a height of 2.25 m. It is connected by a rope to another object so that as it falls, the other object begins to rotate without changing the position of its center of mass. If at the end of this process, the second object has kinetic energy 5.21 J, what is the speed of the first object at that moment?

5.96

7 5.55

6.9

6.47

6.28

6.07

6.69

6.63

6.79

Answer 1

Gravitational acceleration = g = 9.8 m/s²

Mass of the first object that falls = m₁ = 1.22 kg

Height through which the first object falls = h = 2.25 m

Kinetic energy of the second object as the first object falls through a distance of 2.25 m = E₂ = 5.21 J

Speed of the first object after falling through a height of 2.25 m = V

By conservation of energy the potential energy lost by the first object is equal to the sum of the kinetic energy of the first and second object.

V = 5.96 m/s

Speed of the first object after falling through a height of 2.25 m = 5.96 m/s