Question

A (1.30x10^3)-kg car is pulling a (4.5x10^2)-kg trailer along level ground. Friction of the road on...

A (1.30x10^3)-kg car is pulling a (4.5x10^2)-kg trailer along level ground. Friction of the road on the trailer is negligible. The car accelerates with an acceleration of (1.520x10^0) m/s2. What is the force exerted by the car on the trailer?

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Answer #1

Given:

Mass of car = 1.3 X 103 kg = 1300 kg

Acceleration of car = 1.520 X10^0 m/s2 = 1.52 m/s2

Mass of trailer = 4.5 X 102 kg = 450 kg

Force of friction = 0

To find:

Force exerted by car on trailer

Soln:

Formula used: Force = mass X acceleration

The acceleration of the trailer = acceleration of car = 1.52 m/s2

Force exerted by car on trailer = mass of trailer X acceleration of trailer = 450 X 1.52 = 684 N

Therefore, force exerted by car on the trailer is 684 N.

NOTE: Since nothing has been said about how acceleration of car will affect acceleration of trailer, so it can be rightly assumed that acceleration of trailer shall be equal to acceleration of car.

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