Question

A (1.30x10^3)-kg car is pulling a (4.5x10^2)-kg trailer along level ground. Friction of the road on...

A (1.30x10^3)-kg car is pulling a (4.5x10^2)-kg trailer along level ground. Friction of the road on the trailer is negligible. The car accelerates with an acceleration of (1.520x10^0) m/s2. What is the force exerted by the car on the trailer?

Homework Answers

Answer #1

Given:

Mass of car = 1.3 X 103 kg = 1300 kg

Acceleration of car = 1.520 X10^0 m/s2 = 1.52 m/s2

Mass of trailer = 4.5 X 102 kg = 450 kg

Force of friction = 0

To find:

Force exerted by car on trailer

Soln:

Formula used: Force = mass X acceleration

The acceleration of the trailer = acceleration of car = 1.52 m/s2

Force exerted by car on trailer = mass of trailer X acceleration of trailer = 450 X 1.52 = 684 N

Therefore, force exerted by car on the trailer is 684 N.

NOTE: Since nothing has been said about how acceleration of car will affect acceleration of trailer, so it can be rightly assumed that acceleration of trailer shall be equal to acceleration of car.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A 630 kg car pulling a 470 kg trailer accelerates forward at a rate of 2.15...
A 630 kg car pulling a 470 kg trailer accelerates forward at a rate of 2.15 m/s2. Assume frictional forces on the trailer are negligible. Ignore air drag. What is the resultant force exerted by the car on the road? (Assume that the forward direction is along the +x-direction to the right and that the +y-direction points upward. Enter the magnitude in N and the direction in degrees measured from the left of the −y-direction.)
A 1000-kg car pulls a boat on a trailer. (a) What is the magnitude of the...
A 1000-kg car pulls a boat on a trailer. (a) What is the magnitude of the total force that resists the motion of the car, boat, and trailer, if the car exerts a 2100-N force on the road and produces an acceleration of 0.428 ?/?2? The mass of the boat plus trailer is 666 kg. (b) What is the magnitude of the force in the hitch between the car and the trailer if 80% of the resisting forces are experienced...
three 1500 kg cars are driving at 25m/s along the road. Car A is on a...
three 1500 kg cars are driving at 25m/s along the road. Car A is on a flat portion of the road, car B is at the bottom of a hill and car C is at the top of a hill. (a)Determine the normal force that the road exerts on each car. Suppose each car suddenly brakes hard and starts to skid. (b) Determine the magnitude and direction of each car's acceleration. The coefficient of kinetic friction between the tires and...
A 2300 kg car moving at an initial speed of 25 m/s along a horizontal road...
A 2300 kg car moving at an initial speed of 25 m/s along a horizontal road skids to a stop in 50 m. (Note: When stopping without skidding and using conventional brakes, 100 percent of the kinetic energy is dissipated by friction within the brakes. With regenerative braking, such as that used in hybrid vehicles, only 70 percent of the kinetic energy is dissipated.) (a) Find the energy dissipated by friction. 718750 Incorrect: Your answer is incorrect. kJ (b) Find...
a car accelerates uniformly from rest to 24.1 m/s in 9 s along a level stretch...
a car accelerates uniformly from rest to 24.1 m/s in 9 s along a level stretch of road. Ignoring friction , determine the average power required to accelerate the car if the mass of the car is 1,131 kg
A 1700-kg truck and a 1000-kg car are parked with their rear bumpers nearly touching each...
A 1700-kg truck and a 1000-kg car are parked with their rear bumpers nearly touching each other in a level parking lot. Both vehicles have their brakes off so that they are free to roll. A man sitting on the rear bumper of the truck exerts a constant horizontal force on the rear bumper of the car with his feet, and the car accelerates at 1.2 m/s2. Ignore any friction between the tires and the parking lot surface. The direction...
You pull a your friend along in a sled (combined mass is 65 kg), by pulling...
You pull a your friend along in a sled (combined mass is 65 kg), by pulling the rope at an upward angle of 20 degrees with respect to the ground with enough force to keep the sled moving at a constant velocity of m/s. The coefficient of kinetic friction between the ground and the sled is 0.15. (a) Draw a force diagram for the friend/sled system. (b) Once you get to constant velocity, you pull the sled 15 m. What...
The friction between the tires of a car and a flat road provides the centripetal force...
The friction between the tires of a car and a flat road provides the centripetal force for a turn. For a 1800 kg car travelling at 25 m/s on a curve of radius 100 m: a. Calculate the normal force on the car from the road. b. Calculate the centripetal force required to turn the car safely. c. Calculate the minimum coefficient of static friction between the tires and road for the car to turn safely. d. Ice on the...
A box (400 kg) sits inside the trailer of a semitruck traveling at a speed of...
A box (400 kg) sits inside the trailer of a semitruck traveling at a speed of 20 m/s (~ 44 mph). Suddenly, a car in front of the truck stops in the road. The driver of the truck hits the brakes to bring the truck to a stop. Assume that the coefficient of static friction µs = 0.7 between the box and the floor of the trailer. Assume g = 10 m/s2. When the truck slows down while traveling left,...
A car starts from a state of rest and drives along a level, straight road. For...
A car starts from a state of rest and drives along a level, straight road. For the first 30 s, the car speeds up with a constant acceleration of 2.50 m/s 2 , after which it continues at the constant velocity that it has acquired for the next 5.00 minutes, at which time the brakes are applied, and there is an acceleration of -2.2 m/s 2 until the car stops. What is the total displacement of the car from its...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT