Question

The electric field between two square metal plates is 350 N/CN/C . The plates are 2.0 mm on a side and are separated by 1.0 cm. What is the charge on each plate (assume equal and opposite)? Neglect edge effects.

Answer #1

comment

Charge on each plate was found to be 1.24*10^-14 C with their respective signs.

How much energy is stored by the electric field between two
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.

Two large metal plates of area 7.00 m.^2 face each other. They
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Two large metal plates of area 5.36 m.^2 face each other. They
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An electric field of 120 N/C is maintained between two plates
separated by 10.0 cm. A positive charged particle of mass 1.92 x
10-20 kg is placed at the positive plate and released.
If its speed at the negative plate is 21,000 m/s:
A) find the work done on the charge.
B) find the potential difference between the plates
C) find the charge on the particle

An electric field of 120 N/C is maintained between two plates
separated by 10.0 cm. A positive charged particle of mass 1.92 x
10-20 kg is placed at the positive plate and released.
If its speed at the negative plate is 21,000 m/s, find:
a)the work done on the charge.
b)the potential difference between the plates
c) the charge on the particle.
Show all the steps and state the answer as clear as possible
please. Thank you.

Two thin parallel conducting plates are placed 2.0 cm apart.
Each plate is 2.0 cm on a side; one plate carries a net charge of
8.0μC,8.0μC, and the other plate carries a net charge of
−8.0μC.−8.0μC. What is the charge density on the inside surface of
each plate? What is the electric field between the plates?

. If a capacitor has opposite 5.2 C charges on the
plates, and an electric field of 2.0 kV/mm is desired between the
plates, what is each plate area?

A capacitor consists of two square metal plates of side 200 mm,
separated by an air space 2.0 mm wide. The capacitor is charged to
a voltage of 200 V and a sheet of glass having a relative
permittivity of 6 is placed between the metal plates immediately
they are disconnected from the supply. Calculate: (a) the
capacitance with air dielectric; (b) the capacitance with glass
dielectric; (c) the voltage across the capacitor after the glass
plate has been inserted;...

Two charged, square plates, separated by a distance of 27.5 cm
and each with a side length of 44.8 cm, make up a parallel-plate
capacitor. The electric field inside the plates is 2.80×103 N/C. If
the separation distance is halved, what would the electric field
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The electric field between the plates of a
paper-separated (k=3.75) capacitor is 8.245104 V/m. The plates are
1.95 mm apart, and the charge on each plate is 0.775 C. Determine
the capacitance of this capacitor and the area of each plate.

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