Find the force of electrical attraction between a proton and an electron that are 8.4 10-11 m apart. (Enter the magnitude only.)
N
Compare this to the gravitational force between these particles.
solution-
a)the electric force between
where =charge magnitude on electron or proton=1.60*10^-19C
r=seperation distance =8.4*10^-11m
K=constant=8.99*10^9Nm^2/C^2
therefore
=3.26*10^-8N..................answer
b) Gravitational force
where G=gravity constant =6.67*10-11Nm^2/kg^2
Me=mass of electron=9.11*10^-31kg
Mp= mass of proton=1.67*10^-27kg
therefore Fg
=1.44*10^-47N
the ratio of electric to the gravitational force between the electron and proton=Fe/Fg
=3.26*10^-8N/1.44*10^-47N
=2.26*10^39
(the electric force is 2.26*10^39 times larger than the gravitational force)
Get Answers For Free
Most questions answered within 1 hours.