Vultures make use of air thermals by spiraling upward on them. Say a particular vulture is spiraling in a radius of 7.00 m and makes one complete turn every 2 s. It is rising vertically at a constant rate of 2 m/s.
a. What is its speed relative to the ground?
b. What is the acceleration?
c. What is the angle between the bird’s velocity vector and the horizontal.
given ,
radius (R) = 7 m
time (T) = 2 s
constant rate ( Vc ) = 2 m/s
a)
Speed = sqrt(Vc^2 + Vab^2) [ Vab = 2*pi*R/T]
= sqrt(Vc^2 + (2*pi*R / T)^2)
= sqrt(2^2 + (2*3.14*7 / 2)^2)
=sqrt(4 + 483.12)
= 22.071 m/s
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b)
acceleration = 4* (pi)^2 *R / T^2
= 4 * 3.14^2 * 7 / 2^2
= 276.069 / 4
= 69.017 m/s^2
===================================
c)
angle(theta) = tan^-1 ( Vc / Vab) [ Vab = 2*pi*R/T]
=tan^-1(2 / 21.98)
= tan^-1(0.091)
= 5.2 degrees
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