Question

The speed of a block (weight= 10N) sliding across a horizontal ice surface decreases at the...

The speed of a block (weight= 10N) sliding across a horizontal ice surface decreases at the rate of 1.5 m/s^2 . whats The coefficient of kinetic friction between the ice amd the block?

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Answer #1

By force balance on block in horizontal direction,

Fnet = m*a

Fr = m*a

here, Fr = friction force on block = -*N (As, friction force acts in opposite direction of motion.)

N = normal force = m*g

a = acceleration of block = -1.5 m/s^2

So,

-*N = m*a

-*m*g = m*a

= -a/g = -(-1.5)/9.81

= 0.153 = coefficient of kinetic friction between the ice amd the block

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