Question

You are dragging a rubber tire on the concrete floor. The upward force exerted on the...

  1. You are dragging a rubber tire on the concrete floor. The upward force exerted on the tire from the floor is 30N. μs = 1 μk = 0.8

    1. What is the type of force that is being described above?

    1. What is Ff when the tire is moving?

    2. What would Ff be if you are using maximum force but the tire has not started moving yet?

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Answer #1

The 30 N force which is exerted by ground on the tire is the normal reaction force that the ground exerts on the tire. It is equal and opposite to the normal force that tire exerts on the ground.

Ff is basically friction force and is given by product of coefficient of friction and Normal force.

When tire is moving, Ff is coefficient of kinetic friction*Normal force=0.8*30=24 N

When tire is not moving and applied force is maximum, then Ff is coefficient of static friction*Normal force=1*30=30 N

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