Question

A parallel plate capacitor is connected to a constant external voltage supply for a long time...

A parallel plate capacitor is connected to a constant external voltage supply for a long time and stores 8.10 mJ of energy. We now fully fill the air-gap with a dielectric material of dielectric constant 38.93, while keeping the capacitor connected to the voltage supply. How much energy will the capacitor store? Give your answer in units of mJ.

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

In this question, Area(A), Gap(d) and supply voltage (V) is constant so this will be cancelled at the time of division of equations.

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A parallel plate capacitor, in which the space between the plates is filled with a dielectric...
A parallel plate capacitor, in which the space between the plates is filled with a dielectric material with dielectric constant κ = 4.3, has a capacitance of C=968 μF and it is connected to a battery whose voltage is V=25 V and fully charged. Once fully charged, while still connected to the battery, dielectric material is removed from the capacitor. How much change occurs in the energy of the capacitor; final energy minus initial energy? Express your answer in units...
A parallel plate capacitor, in which the space between the plates is filled with a dielectric...
A parallel plate capacitor, in which the space between the plates is filled with a dielectric material with dielectric constant κ = 4.7, has a capacitance of C=1,018 μF and it is connected to a battery whose voltage is V=10 V and fully charged. Once it is fully charged, it is disconnected from the battery and without affecting the charge on the plates, dielectric material is removed from the capacitor. How much change occurs in the energy of the capacitor;...
A parallel plate capacitor, in which the space between the plates is filled with a dielectric...
A parallel plate capacitor, in which the space between the plates is filled with a dielectric material with dielectric constant κ = 6.2, has a capacitance of C=4,650 μF and it is connected to a battery whose voltage is V=37 V and fully charged. Once it is fully charged, it is disconnected from the battery and without affecting the charge on the plates, dielectric material is removed from the capacitor. How much change occurs in the energy of the capacitor;...
Consider a parallel plate capacitor with plate dimensions of 10 cm x 10 cm and a...
Consider a parallel plate capacitor with plate dimensions of 10 cm x 10 cm and a gap spacing of 2.00 cm. The capacitor is connected to a battery supplying a voltage across the capacitor of 2.00 kV. After the capacitor is fully charged, the battery is disconnected. A dielectric material is then inserted into the vacuum space to completely fill the capacitor. This result in a decrease of the capacitor voltage to 1.00 kV. a.Find the vacuum electric field between...
A parallel plate capacitor, in which the space between the plates is filled with a dielectric...
A parallel plate capacitor, in which the space between the plates is filled with a dielectric material with dielectric constant κ = 9.8, has a capacitance of C=472 μF and it is connected to a battery whose voltage is V=30 V and fully charged. Once fully charged, while still connected to the battery, dielectric material is removed from the capacitor. How much change occurs in the energy of the capacitor; final energy minus initial energy?
A parallel plate capacitor in air is constructed with a plate area of 7.75cm2 and a...
A parallel plate capacitor in air is constructed with a plate area of 7.75cm2 and a plate separation of 0.664mm. A) Determine the value of the capacitance of this parallel plate capacitor. B) This capacitor is placed across a 21.0 V battery and allowed to fully charge. What is the value of this charge with included units. C) When fully charged, what is the energy stored inside the capacitor? D) With the battery still connected, a pyrex glass dielectric material...
1 A parallel plate capacitor is connected to a battery and becomes fully charged the capacitor...
1 A parallel plate capacitor is connected to a battery and becomes fully charged the capacitor is then disconnected and the separation between the plates is halved in such a way that so charge leaks off As the plate separation is being halved which of the following parameters remains constant? An air filled k=1 ideal parallel plate capacitor has a capacitance of C. If the area of the plates is doubled insert a dielectric material k=2 and the distance between...
A dielectric-filled parallel-plate capacitor has plate area A = 30.0 cm2 , plate separation d =...
A dielectric-filled parallel-plate capacitor has plate area A = 30.0 cm2 , plate separation d = 7.00 mm and dielectric constant k = 5.00. The capacitor is connected to a battery that creates a constant voltage V = 10.0 V . Throughout the problem, use ϵ0 = 8.85×10−12 C2/N⋅m2 . a. The dielectric plate is now slowly pulled out of the capacitor, which remains connected to the battery. Find the energy U2 of the capacitor at the moment when the...
A dielectric-filled parallel-plate capacitor has plate area A = 30.0 cm2 , plate separation d =...
A dielectric-filled parallel-plate capacitor has plate area A = 30.0 cm2 , plate separation d = 8.00 mm and dielectric constant k = 4.00. The capacitor is connected to a battery that creates a constant voltage V = 5.00 V . Throughout the problem, use ϵ0 = 8.85×10−12 C2/N⋅m2 . Part A- Find the energy U1 of the dielectric-filled capacitor. Part B- The dielectric plate is now slowly pulled out of the capacitor, which remains connected to the battery. Find...
A dielectric-filled parallel-plate capacitor has plate area A = 25.0 cm2 , plate separation d =...
A dielectric-filled parallel-plate capacitor has plate area A = 25.0 cm2 , plate separation d = 7.00 mm and dielectric constant k = 5.00. The capacitor is connected to a battery that creates a constant voltage V = 15.0 V . Throughout the problem, use ϵ0 = 8.85×10−12 C2/N⋅m2 . Part A Find the energy U1 of the dielectric-filled capacitor. Part B The dielectric plate is now slowly pulled out of the capacitor, which remains connected to the battery. Find...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT