Question

Consider the circuit shown in the figure below, where

R₁ = 5.00 Ω,

R₂ = 8.00 Ω,

and

= 6.00 V.

A rectangular circuit begins at the positive terminal of a battery labeled emf ℰ, which is on the bottom side of the rectangle. The circuit extends up and to the left to a 2.00 Ω resistor on the top side of the rectangle. To the right of the 2.00 Ω resistor, the circuit splits into two parallel horizontal branches.

• The top branch splits into two parallel horizontal sub-branches. There is a 10.0 Ω resistor on the top sub-branch and a 5.00 Ω resistor on the bottom sub-branch. The sub-branches then recombine and the top branch extends to the right to a resistor of resistance R₂.
• The bottom branch contains a resistor of resistance R₁.

The top and bottom branches then recombine and the circuit extends down and to the left until it reaches the negative terminal of the battery.

(a)

Find the voltage (in V) across

R₁.

V

(b)

Find the current (in A) in

R₁.

A

Answer 1

Part A

V1 = 3.82 V

Part B

I1 = 0.76 A