Question

Unfortunately, ProtonMan did not realize that CaptainShield also watched his video blogs so he knew that ProtonMan had planned to fly past CaptainShields right hand side, at a distance of about 2.5 m (just close enough so he could see CaptainShields dumb surprised face). CaptainShield, still knowing ProtonMans mass (100 kg), velocity (50 m/s), and charge (4 mC) decided to lay a trap. His trap included laying down a plate which emits a uniform magnetic field. CaptainShield wanted his trap to force ProtonMan to spin around him in a circular path, allowing CaptainShield ample time to laugh and gloat before arresting ProtonMan. What magnetic field strength and direction should CaptainShields plate emit?

Answer 1

The concept used in this question is of magnetic force acting on a protona man moving with velocity v in presence of magnetic field along the center , as this force acts along the center which provides the necessary centrepetal force required for the proton man to move in the circular path .

Magnetic field direction is out of page which is denoted by dot in figure .

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