Question

Four charges (-e,e,-e,e) in a row are separated from their neighboring charges by 3×10^(-10)m. Calculate the work required to remove the positive charge on the right side to infinity.

Answer #1

**let d = 3*10^-10 m
q1 = -e
q2 = +e
q3 = -e
q4 = +e
potential at the location of right side charge,**

**Vi = k*q1/(3*d) + k*q2/(2*d) + k*q3/d**

**= k*(-e)/(3*d) + k*e/(2*d) + k*(-e)/d**

**= -(5/6)*k*e/d**

**potential at infinite distance, Vf = 0**

**Workdone in moving the charge q4 to infinity, W = q4*(Vf
- Vi)**

**= e*(0 - (-(5/6)*k*e/d ) )**

**= (5/6)*k*e^2/d**

**= (5/6)*9*10^9*(1.6*10^-19)^2/(3*10^-10)**

**= 6.4*10^-19 J
<<<<<<<<<<<<-----------------------------Answer**

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