Question

Please please print legibly and include any formulas. I won't upvote if I can't read your handwriting... thank you!

**In a photoelectric effect experiment, an unknown metal
is illuminated by light. If the Kinetic Energy of the ejected
electrons when illuminated by light of 300nm wavelength is 3.89
times larger than the kinetic energy when the same metal is
illuminated by light of 400nm, determine what is the Binding Energy
(eV) of the metal?**

Answer #1

From Einstein's Photo electric Equation,

Energy of Photon = Binding Energy + Kinetic Energy

From the question,

' h ' and ' c ' are constant ; substituting all values/

Substituting in Eqn (2)

Binding Energy,

In a photoelectric e↵ect experiment, the maximum kinetic energy
of electrons ejected from a cesium metal plate is found to be
0.57eV when the plate is illuminated with 500 nm light.
(a) Given what we know about the relation of wavelength and
energy, how much energy does a single photon of 500 nm light
have?
(b) Given the results of this experiment, how much energy must
the electron have used to break free of the atom?
(c) When the same...

2a) When a metal surface is illuminated by light of wavelength
310 nm, the
measured maximum kinetic energy of the emitted electrons is 0.50
eV. Calculate the
metal plate’s work function φ in units of eV.
b) In the rest frame of an ejected electron from the photoelectric
experiment in part a),
an incident γ-ray with an energy of 0.25 MeV interacts with the
electron. Following
the collision, the γ-ray has a final energy of 0.1 MeV. Calculate
the angle...

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