Question

1. (a) The peak current measured in an AC circuit is 20 mA. Calculate the peak voltage across and RMS current through a 450 ohms resistor that is in the circuit     (5 points)                                                                                                                                                                                                                                                                                                                                 

(b)  A 6.0 cm long wire carrying a current of 5.0 A is placed in a magnetic field experiences a force of 0.0225N when the angle between the wire and the magnetic field is 30 degrees. Calculate the force on the wire when the magnetic field is perpendicular to the length of the wire.            

I WILL RATE

Answer 1

here,

(A)

the peak current , Im = 20 mA

the rms current , Irms = Im/sqrt(2)

Irms = 20 /sqrt(2) mA = 14.2 mA

the peak voltage , Vm = Im * 450

Vm = 20 * 450 mV = 9 V

b)

the magnetic force , F = B * I *L * sin(theta)

when theta1 = 30 degree , the magnetic force , F1 = 0.0225 N

when theta2 = 90 degree , let the magnetic force be F2

F2 /F1 = sin(theta2) /sin(theta1)

F2 = 0.0225 /sin(30) N

F2 = 0.045 N

the force on the wire when the magnetic field is perpendicular to the length of the wire is 0.045 N