Question

solve differential equation

y^(4) +2y''' +2y''=0

Answer #1

Solve the differential equation(be sure to include
detailed steps): y'-2y+4=0, y(1)=4

Solve the differential equation
(1-y)dx-x^2y^2dy=0

Solve the Differential Equation:
(2y^4 + xy)dx - (6x^2) dy= 0

Solve the following differential equation using Laplace dy/dt
+2y=12sin4t y(0) =10

Solve the differential equation y''' - 2y'' + y' = 2e^x - 6x

Solve the differential equation by variation of parameters. y''
+ 3y' + 2y = 1/(4+e^x)

Solve the following 2nd Order differential equation and find
y(x):
y'' + 2y' +y = x + e-x
y(0) = 0, y'(0) = 0.

Solve the given differential equation by undetermined
coefficients.
y'' − 2y' +
y = x3 +
5x

Solve the given differential equation by undetermined
coefficients.
y'' − 2y' + y = (6x − 2)e^x

Given the differential equation
y''−2y'+y=0, y(0)=1, y'(0)=2
Apply the Laplace Transform and solve for Y(s)=L{y}
Y(s) =
Now solve the IVP by using the inverse Laplace Transform
y(t)=L^−1{Y(s)}
y(t) =

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