Question

A brass plug is to be placed in a ring made of iron. At 15∘C, the...

A brass plug is to be placed in a ring made of iron. At 15∘C, the diameter of the plug is 8.864 cm and that of the inside of the ring is 8.855 cm .

They must both be brought to what common temperature in order to fit?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A brass plug is to be placed in a ring made of iron. At 15∘C, the...
A brass plug is to be placed in a ring made of iron. At 15∘C, the diameter of the plug is 8.900 cm and that of the inside of the ring is 8.889 cm . They must both be brought to what common temperature in order to fit?
A brass plug is to be placed in a ring made of iron. At 16 ?C,...
A brass plug is to be placed in a ring made of iron. At 16 ?C, the diameter of the plug is 8.793 cm and that of the inside of the ring is 8.778 cm . They must both be brought to what common temperature in order to fit? What if the plug were iron and the ring brass?
A brass plug is to be placed in a ring made of iron. At 20 ∘C,...
A brass plug is to be placed in a ring made of iron. At 20 ∘C, the diameter of the plug is 8.735 cm and that of the inside of the ring is 8.722 cm . A) They must both be brought to what common temperature in order to fit? B) What if the plug were iron and the ring brass?
A brass plug is to be placed in a ring made of iron. At 10 ∘C,...
A brass plug is to be placed in a ring made of iron. At 10 ∘C, the diameter of the plug is 8.741 cm and that of the inside of the ring is 8.729 cm . 1.They must both be brought to what common temperature in order to fit? 2.What if the plug were iron and the ring brass?
A brass plug is to be placed in a ring made of iron. At 20°C, the...
A brass plug is to be placed in a ring made of iron. At 20°C, the diameter of the plug is 8.740 cm and that of the inside of the ring is 8.730 cm. (a) They must both be brought to what common temperature in order to fit? (b) Repeat part (a) if the plug were iron and the ring brass.
A circular brass plug needs to pass through a square hole in an iron sheet. At...
A circular brass plug needs to pass through a square hole in an iron sheet. At room temperature (20◦C), the diameter of the plug is 8.755 cm and the length of each side of the square is 8.740 cm. At what temperature must the iron sheet be brought in order for the brass plug to fit through the square hole? The brass plug is not heated. The coefficient of linear expansion for iron is 12 × 10−6/◦C. (The answer is...
A brass ring with inner diameter 2.00 cm and outer diameter 3.00 cm needs to fit...
A brass ring with inner diameter 2.00 cm and outer diameter 3.00 cm needs to fit over a 2.00-cm-diameter steel rod, but at 20 degrees Celsius the hole through the brass ring is 40 μm too small in diameter. To what temperature, in degrees Celsius, must the rod and ring be heated so that the ring just barely slips over the rod?
A steel rod is 3.500 cm in diameter at 15.00°C. A brass ring has an interior...
A steel rod is 3.500 cm in diameter at 15.00°C. A brass ring has an interior diameter of 3.493 cm at 15.00°C. At what common temperature will the ring just slide onto the rod? °C
A steel rod is 3.000 cm in diameter at 33.0 °C. A brass ring has an...
A steel rod is 3.000 cm in diameter at 33.0 °C. A brass ring has an interior diameter of 2.992 cm at 33.0 °C. At what common temperature will the ring just slide onto the rod? The coefficients of linear expansion of steel and brass are 1.100×10-5 , 1.900×10-5 /°C, respectively, answer in °C.
At 20.0°C, an aluminum ring has an inner diameter of 5.00 cm and a brass rod...
At 20.0°C, an aluminum ring has an inner diameter of 5.00 cm and a brass rod has a diameter of 5.055 cm. (a)If only the ring is warmed, what temperature must it reach so that it will just slip over the rod? (b) If both the ring and the rod are warmed together, what temperature must they both reach so that the ring barely slips over the rod? (c) Why might the temperature value of part (b)pose problems for this...