Question

regarding the contributions of phonons to the specific heat of a solid when is there a...

regarding the contributions of phonons to the specific heat of a solid

when is there a contribution of optical modes? if you want to determine this contribution as an insulator ,would you measure the specific heat at a low or high temperature and why

Homework Answers

Answer #1

Solution

Answer to the first part : As name suggest that optical modes i.e they are of very high frequency , which must generate at high temperature . So we can state that optical modes generally contribute to the specific heat of solid at high temperature .i.e at T > where is the De-bye temperature , which act as cut off for the phonon

Now come to second part, since optical modes are generated at higher temperature, so it is better to measure the specific heat at high temperature. But is the material dependent , it may be low as 5-10K or high as a few hundred K. So one has to calculate the De-bye temperature

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
1. When a solid dissolves in water, heat may be evolved or absorbed. The heat of...
1. When a solid dissolves in water, heat may be evolved or absorbed. The heat of dissolution (dissolving) can be determined using a coffee cup calorimeter. In the laboratory a general chemistry student finds that when 6.20 g of CsClO4(s) are dissolved in 115.60 g of water, the temperature of the solution drops from 22.87 to 19.50 °C. Based on the student's observation, calculate the enthalpy of dissolution of CsClO4(s) in kJ/mol. Assume the specific heat of the solution is...
When first calculating the specific heat of your metal, you did not include the heat absorbed...
When first calculating the specific heat of your metal, you did not include the heat absorbed by the calorimeter. How did this effect your original answer for the specific heat of your metal? The original answer was too low. There was no effect on the original answer Depends on the metal chosen. The original answer was too high.
Specific heat is the heat necessary to raise the temperature of 1kg of a given material...
Specific heat is the heat necessary to raise the temperature of 1kg of a given material by 1∘C. This specific heat value varies by material with metals having relatively low specific heat with organic materials and water being very high. The specific heat of mercury is 140 J/kg∘C and the specific heat of water is 4190 J/kg∘C. Part A 106 J of heat energy are transferred to 26.5 g of mercury. By how much does the temperature increase? Part B...
The specific heat of water in its solid phase (ice) is 2090 J/(kg K), while in...
The specific heat of water in its solid phase (ice) is 2090 J/(kg K), while in the liquid phase (water) its specific heat is 4190 J/(kg K). Water's latent heat of fusion is 333,000 J/kg. If you have a 2kg block of ice at -90 degrees C and you add 1,000,000 J of heat, what is its new temperature?
When a solid dissolves in water, heat may be evolved or absorbed. The heat of dissolution...
When a solid dissolves in water, heat may be evolved or absorbed. The heat of dissolution (dissolving) can be determined using a coffee cup calorimeter. In the laboratory a general chemistry student finds that when 18.53 g of Cs2SO4(s) are dissolved in 100.40 g of water, the temperature of the solution drops from 25.54 to 22.92 °C. The heat capacity of the calorimeter (sometimes referred to as the calorimeter constant) was determined in a separate experiment to be 1.85 J/°C....
When a solid dissolves in water, heat may be evolved or absorbed. The heat of dissolution...
When a solid dissolves in water, heat may be evolved or absorbed. The heat of dissolution (dissolving) can be determined using a coffee cup calorimeter. In the laboratory a general chemistry student finds that when 4.13 g of CuCl2(s) are dissolved in 111.70 g of water, the temperature of the solution increases from 25.33 to 28.58 °C. The heat capacity of the calorimeter (sometimes referred to as the calorimeter constant) was determined in a separate experiment to be 1.89 J/°C....
Specific heat of an adsorbed mobile monolayer. If the surface of some solid is maintained in...
Specific heat of an adsorbed mobile monolayer. If the surface of some solid is maintained in a reasonably good vacuum, a single layer of molecules, one molecular diameter thick, can form on this surface. (The molecules are then said to be adsorbed on the surface.) The molecules are held to this surface by forces exerted on them by the atoms of the solid, but they may be quite free to move in two dimensions on this surface. They form then,...
The specific heat of a certain solid follows the equation Cp = bT³ between 0 and...
The specific heat of a certain solid follows the equation Cp = bT³ between 0 and 250 K. Since b = 3.5J / K³, determine the entropy of this solid at 50 K according to the third law (in kJ / K)
A student obtains the following data in a calorimetry experiment designed to measure the specific heat...
A student obtains the following data in a calorimetry experiment designed to measure the specific heat of aluminum. Initial temperature of water and calorimeter 70.4°C Mass of water 0.403 kg Mass of calorimeter 0.04 kg Specific heat of calorimeter 0.60 kJ/kg·°C Initial temperature of aluminum 27.1°C Mass of aluminum 0.196 kg Final temperature of mixture 66.4°C (a) Use these data to determine the specific heat of aluminum. J/kg · °C (b) Is your result within 15% of 900 J/kg ·...
The specific heat of mercury is 138 J/kg°C. Determine the latent heat of fusion of mercury...
The specific heat of mercury is 138 J/kg°C. Determine the latent heat of fusion of mercury using the following calorimeter data: 1.30 kg of solid Hg at its melting point of -39.0°C is placed in a 0.620 kg aluminum calorimeter with 0.400 kg of water at 12.80°C; the resulting equilibrium temperature is 2.91°C
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT