Question

**An electron is traveling with velocity 10 m/s in the +y direction and an external magnetic field of strength 100 W/m2 is applied in the +z direction. Describe the effect and resulting motion of the electron due to the applied field.**

Answer #1

Determine the magnitude and direction of the force on an
electron traveling 8.00×10^5 m/s horizontally to the east in a
vertically upward magnetic field of strength 0.60T.

A proton, traveling with a velocity of 2.7 106 m/s due east,
experiences a maximum magnetic force of 8.0 10-14 N. The direction
of the force is straight down, toward the surface of the earth.
What is the magnitude and direction of the magnetic field B,
assumed perpendicular to the motion?

An electron has an initial velocity of 2×106 m/s in the +x
direction. It enters a uniform electric field E = 410 N/C which is
in the +y direction. By how much, and in what direction, is the
electron deflected after traveling 9 cm in the +x direction in the
field ?

A proton, traveling with a velocity of 3.2 × 106 m/s
due east, experiences a magnetic force that has a maximum magnitude
of 8.2 × 10-14 N and direction of due south. What are
the magnitude and direction of the magnetic field causing the
force? If the field is up, then enter a number greater than zero.
If the field is down, then enter a number less than zero.

A proton, traveling with a velocity of 7.3 × 106 m/s
due east, experiences a magnetic force that has a maximum magnitude
of 8.7 × 10-14 N and direction of due south. What are
the magnitude and direction of the magnetic field causing the
force? If the field is up, then enter a number greater than zero.
If the field is down, then enter a number less than zero.

A proton, traveling with a velocity of 4.9 × 106 m/s
due east, experiences a maximum magnetic force of 8.0 ×
10-14 N. The direction of the force is straight down,
toward the surface of the earth. What is the magnitude and
direction of the magnetic field B, assumed perpendicular
to the motion?
B = Number ___
B) Units ____ ( W,J,No units,V,m,C,T. A, V/m) options
C)____
East, South, West or North
the tolerance is +/-2%

A group of particles is traveling in a magnetic field of unknown
magnitude and direction. You observe that a proton moving at 1.30
km/s in the +x-direction experiences a force of 2.10×10−16 N in the
+y-direction, and an electron moving at 4.50 km/s in the
−z-direction experiences a force of 8.60×10−16 N in the
+y-direction. What is the magnitude of the magnetic field?
b-What is the direction of the magnetic field? (in the
xz-plane)

A group of particles is traveling in a magnetic field of unknown
magnitude and direction. You observe that a proton moving at 1.20
km/s in the +x-direction experiences a force of
2.06×10−16 N in the +y-direction, and an
electron moving at 4.40 km/s in the −z-direction
experiences a force of 8.40×10−16 N in the
+y-direction.
Part A: What is the magnitude of the magnetic field?
Park B: What is the direction of the magnetic field? (in the
xz -plane
Part...

A proton, traveling with a velocity of 6.8 x 106 m/s
due east, experiences a maximum magnetic force of 8.0 x
10-14 N. The direction of the force is straight down,
toward the surface of the earth. What is the magnitude and
direction of the magnetic field B, assumed perpendicular to the
motion?

An electron in a TV camera tube is moving at 5.80×106 m/s in a
magnetic field of strength 93 mT. Without knowing the direction of
the field, what can you say about the greatest and least magnitude
of the force acting on the electron due to the field?
Maximum force? (in N)
Minimum force? (in N)
At one point the acceleration of the electron is 8.365×1016
m/s2. What is the angle between the electron velocity and the
magnetic field? (deg)...

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