Question
1.) The nucleus 10Be decays by electron emission. Determine the maximum energy of the electron emitted...
1.) The nucleus 10Be decays by electron emission. Determine the maximum energy of the electron emitted in this process.
Homework Answers
Answer #1
Solution:
The electron emission or -
decay equation,
104Be 
105Be
Mass defect:
m
= m[104Be ] - m[105Be
]
= 10.01353470 - 10.0129376
= 5.971*10-4 u
Q =
mc2
= 5.971*10-4 *931.5
= 0.5562 MeV
= 556.2 keV.
The emitted nucleus is way heavier than the -
particle and the energy of the antineutrino is also negligible and
therefore the maximum energy of the emitted electron is equal to
the Q value.
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