Question

A uniform solid disk with radius 0.078m has mass 0.84kg. A constant force of 15N is applied as shown. At the instant shown, the angular velocity of the disk is 20rad/s in the −z direction. The length of the string d=0.16mm.

(x̂ x^ is to the right, ŷ y^ is up, and ẑ z^ is out of the page.)

At this instant, what are the magnitude and direction of the angular momentum about the center of the disk?

|L⃗ CM|=

Direction:   +x -x +y -y +z -z No direction

What are the magnitude and direction of the torque on the disk, about the center of mass of the disk?

|τ⃗ CM|=

Direction:   +x -x +y -y +z -z No direction

The string is pulled for 0.16ss. What are the magnitude and direction of the angular impulse τ⃗ CMΔtτ→CMΔt applied to the disk during this time?

|τ⃗ CM|Δt=

Direction:   +x -x +y -y +z -z No direction

After the torque has been applied for 0.16ss, what are the magnitude and direction of the angular momentum about the center of the disk?

Direction:   +x -x +y -y +z -z No direction

At this later time, what are the magnitude and direction of the angular velocity of the disk?

Direction:

Due in 2 hours please help !!

Answer 1