Question

What is the voltage output of a transformer used for rechargeable flashlight batteries if its primary has 525 turns, its secondary has8 turns, and the input voltage is 112 V?
V

(b) What input current is required to produce a 4.00 A output?
mA

(c) What is the power input?
W

Answer 1

Given:

Input voltage (V_p) = 112 V

Primary turns (n_p)= 525

Secondary turns (n_S) = 8

Input current (Ip) = 4.00 A

Here, A transformer consists of two coils - the primary coil and the secondary coil both wound on a soft iron core.

Using the formula,

Secondary voltage (V_s)/ Primary voItage (V_P) = Secondary turns (n_S)/ Primary turns (n_P)

Secondary voltage (V_s) = (8 * 112 V) / 525

= 1.706 V

Similarly, Secondary Current (I_s)/ Primary Current (I_P) = Secondary turns (n_S)/ Primary turns (n_P)

Primary Current (I_P) = (4 A * 525)/8

=262.5 A

c) Power input (Pp) = Ip * Vp = 262.5 * 112

= 29400 W

= 29.4 kW