Question

A 1.3-kΩ resistor and 26.3-mH inductor are connected in series to a Vrms = 120 V...

A 1.3-kΩ resistor and 26.3-mH inductor are connected in series to a Vrms = 120 V AC power source oscillating at a frequency of f = 60 Hz. The voltage as a function of time is given by

V = V0cos(ωt),


where V0 is the amplitude, ω is the angular frequency.

Part (a) What is the amplitude of the source voltage, in volts?

Part (b) Enter an expression for the impedance of the circuit in terms of R, L, f, and π.

Part (c) Enter an expression for the tangent of the phase constant of the circuit in terms of R, L, f, and π.

Part (d) Assume the time dependence of the source voltage is given by V = V0cos377t, where the amplitude V0 is what you calculated in part (a) and the angular frequency is (2π)60 rad/s ≈ 377 rad/s. Select the correct expression for the current in the circuit.

Part (e) Find the current in the circuit, in amperes, at time t = 5.8 s.

Part (f) Find the voltage drop across the resistor, in volts, at time t = 5.8 s.

Part (g) Find the voltage drop across the inductor, in volts, at time t = 5.8 s.

Part (h) Find the average power, in watts, that is dissipated in the resistor.

Part (i) Find the average power, in watts, that is dissipated in the inductor.

Part (j) Find the average power, in watts, that is produced by the source.

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Answer #1

please post the last few questions separately and post the options of question (d)

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