Question

Please solve this physics problem from optics course with
clear detailed steps.

4(a) Two parallel narrow slits in an opaque screen are
illuminated by a normally incident plane wave of wavelength 550 nm.
The slits are separated by 0.10 mm. One of the slits is covered
with a thin plastic sheet of thickness 50 μm and index 1.420. In
what direction do the waves from the two slits interfere with zero
phase difference?

4(b) Fringes of equal thickness are observed when light of
wavelength = 600 nm is incident normally on to a wedge-shaped film
of refractive index 1.50 in air. What is the angle of the wedge if
the fringe separation is 0.05 cm?

Answer #1

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If you have any doubt regarding this partiular question then please comment

1) Two elements have photoelectric work functions given by Wn=
570 eV and Wm= 681 eV, respectively. If both metals are illuminated
by UV radiation of the same wavelength. Calculate the difference of
the maximum kinetic energy of photoelectrons from each surface if
wavelength = 298 nm
1.78 x 10^-17 J
111 J
1.34 x 10^-19 J
2.00 x 10^-16 J
2) Two slits have a separation, 6.34 x 10^-2 m. An interference
pattern is created 9.71 m away from...

Please answer all Parts. Will rate up! Thanks!
Part A:
Two slits have a separation, 7.12×10−3 m. An
interference pattern is created 5.46 m away from the slits, with a
distance 0.832 m between the central bright fringe and the
9th dark fringe below it. What is the wavelength of
light used to create the pattern?
1.79×10−4 m
4.77×10−4 m
0.762 m
1.26×10−4 m
Part B:
Two two-slit experiments are conducted separately in two mediums
to study the effect that...

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