A guitar string with a linear density of 2.0 g/m is stretched between supports that are 60 cm apart. The string is observed to form a standing wave with three antinodes when driven at a frequency of 420 Hz. What are (a) the frequency of the fifth harmonic of this string and (b) the tension in the string?
a)
fn=nth harmonic frequency=nf1 (1)
f1= fundamental frequency
3 antinode means 3rd harmonic f3=420Hz (given) and f5=?
from eqaution (1)
f5=700Hz
b)
using (1) f1=fn/n=f3/3=140Hz
v=velocilty of wave=2Lf1=2x60cmx140Hz=168m/s
L= length of string
T=tension on string
=linear mass density of the string
So Tension on the string T=56.448N
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